Question

what values of y and z make (\triangle qrscong\triangle cba)?

Explanation:

Step1: Set up equation for \(y\)

Since \(\triangle QRS\cong\triangle CBA\), corresponding sides are equal. So \(11y - 37=12y - 49\).
Subtract \(11y\) from both sides: \(-37=y - 49\).
Add \(49\) to both sides: \(y=-37 + 49=12\).

Step2: Set up equation for \(z\)

Also, \(3z + 36=5z\).
Subtract \(3z\) from both sides: \(36 = 2z\).
Divide both sides by \(2\): \(z=\frac{36}{2}=18\).

Answer:

\(y = 12\), \(z = 18\)