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Question
what values of y and z make (\triangle fghcong\triangle cab)?
Step1: Set up equation for \(y\)
Since \(\triangle FGH\cong\triangle CAB\), corresponding sides are equal. So \(6y + 2=9y-22\).
Subtract \(6y\) from both sides: \(2 = 3y-22\).
Add \(22\) to both sides: \(24=3y\).
Divide both sides by \(3\): \(y = 8\).
Step2: Set up equation for \(z\)
Also, \(6z=z + 15\).
Subtract \(z\) from both sides: \(5z=15\).
Divide both sides by \(5\): \(z = 3\).
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\(y = 8\), \(z = 3\)