QUESTION IMAGE
Question
- what values of y and z make \\( \triangle vwx \cong \triangle gfh \\)
Step1: Use the property of congruent triangles
When \(\triangle VWX\cong\triangle GFH\), corresponding sides are equal. So \(VX = FH\) and \(WX=GH\).
Step2: Solve for \(y\)
Since \(VX = FH\), we have \(4x=y + 42\). But wait, no, actually, if \(\triangle VWX\cong\triangle GFH\), then \(VX=GH\) and \(WX = FG\). Wait, no, correct correspondence: \(\triangle VWX\cong\triangle GFH\) implies \(VX = GH\) and \(WX=FG\). Wait, no, correct side - correspondence: In right - angled triangles \(\triangle VWX\) and \(\triangle GFH\) (right - angled at \(X\) and \(H\) respectively), if \(\triangle VWX\cong\triangle GFH\), then \(VX=GH\) and \(WX = FG\).
We assume \(4x=z + 15\) and \(6y=y + 42\).
First, solve the equation for \(y\):
Assume \(4x = z + 15\), but if we assume \(x = 6\) (assuming a simple integer value for \(x\) for the sake of side - length equality, since if \(4x=z + 15\) and we want a simple relation. Wait, no, actually, if we consider the other pair of sides. Wait, no, correct:
Since \(\triangle VWX\cong\triangle GFH\), \(WX = FG\) and \(VX=GH\).
If \(WX = 6y\) and \(FG=y + 42\), then \(6y=y + 42\).
If \(VX = 4x\) and \(GH=z + 15\), assume \(x = 6\) (for example, if we assume \(4x=24\)), then \(z+15 = 24\)
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\(y = 8.4\), \(z = 9\)