Question

1. what is the value of \\(\frac{x^3 + 20}{x^2 - 40}\\) when \\(x = -6\\)

Explanation:

Step1: Substitute \( x = -6 \) into the numerator

Calculate \( x^3 + 20 \) when \( x = -6 \).
\( (-6)^3 + 20 = -216 + 20 = -196 \)

Step2: Substitute \( x = -6 \) into the denominator

Calculate \( x^2 - 40 \) when \( x = -6 \).
\( (-6)^2 - 40 = 36 - 40 = -4 \)

Step3: Divide numerator by denominator

Divide the result from Step1 by the result from Step2.
\( \frac{-196}{-4} = 49 \)

Answer:

49