Question

what must be the value of x so that lines a and b are parallel lines cut by transversal f? 10 20 22 32

Explanation:

Step1: Use the property of same - side exterior and interior angles

When two parallel lines are cut by a transversal, same - side exterior and interior angles are supplementary. So, \((6x - 36)+96 = 180\).

Step2: Simplify the equation

Simplify the left - hand side of the equation: \(6x-36 + 96=6x + 60\). The equation becomes \(6x+60 = 180\).

Step3: Solve for \(x\)

Subtract 60 from both sides: \(6x=180 - 60\), so \(6x = 120\). Then divide both sides by 6: \(x=\frac{120}{6}=20\).

Answer:

20