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Question
if \\( \angle w y x \cong \angle w y z \\), \\( w x = 3 s \\), and \\( w z = s + 30 \\), what is the value of \\( s \\)?
Step1: Apply the Angle - Bisector Theorem (HL Congruence for Right Triangles)
Since \( \angle WYX\cong\angle WYZ\), \( \angle WXY = \angle WZY=90^{\circ}\), and \( WY = WY\) (common side), by the Hypotenuse - Leg (HL) congruence criterion for right - triangles, \( \triangle WXY\cong\triangle WZY\).
Step2: Set up the equation based on congruent sides
If \( \triangle WXY\cong\triangle WZY\), then \( WX = WZ\). Given \( WX = 3s\) and \( WZ=s + 30\), we set up the equation \(3s=s + 30\).
Step3: Solve the equation for \(s\)
Subtract \(s\) from both sides of the equation \(3s=s + 30\). We get \(3s−s=s + 30−s\), which simplifies to \(2s=30\).
Divide both sides by 2: \(s=\frac{30}{2}\).
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