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what is the sum of the interior angles in a 35 - gon?

Question

what is the sum of the interior angles in a 35 - gon?

Explanation:

Step1: Recall the formula for the sum of interior angles

The formula for the sum of interior angles of an \(n -\)gon is \((n - 2)\times180^{\circ}\), where \(n\) is the number of sides of the polygon.

Step2: Substitute \(n = 35\) into the formula

When \(n=35\), we have \((35 - 2)\times180^{\circ}\).
First, calculate \(35−2=33\).
Then, \(33\times180^{\circ}=5940^{\circ}\).

Answer:

\(5940^{\circ}\)