Question

what is the solution to the equation $4 + \sqrt3{2y} = 6$? $y = 2000$ $y = 1$ $y = 4$ $y = 500$

Explanation:

Step1: Isolate the cube root term

Subtract 4 from both sides:
$$\sqrt[3]{2y} = 6 - 4$$
$$\sqrt[3]{2y} = 2$$

Step2: Eliminate the cube root

Cube both sides of the equation:
$$(\sqrt[3]{2y})^3 = 2^3$$
$$2y = 8$$

Step3: Solve for y

Divide both sides by 2:
$$y = \frac{8}{2}$$
$$y = 4$$

Answer:

y = 4