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Question
what is the slope of a trend line that passes through the points \\((-3, 3)\\) and \\((18, 26)\\)?
\\(\bigcirc\\) \\(\frac{15}{29}\\)
\\(\bigcirc\\) \\(\frac{21}{23}\\)
\\(\bigcirc\\) \\(\frac{23}{21}\\)
\\(\bigcirc\\) \\(\frac{29}{15}\\)
Identify the given points
$$
(x_1, y_1) = (-3, 3),\quad (x_2, y_2) = (18, 26)
$$
Apply the slope formula
$$
m = \frac{y_2 - y_1}{x_2 - x_1}
$$
Calculate the slope value
$$
m = \frac{26 - 3}{18 - (-3)} = \frac{23}{18 + 3} = \frac{23}{21}
$$
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- (A) \(\frac{15}{29}\)
- (B) \(\frac{21}{23}\)
- (C) \(\frac{23}{21}\) (Correct answer)
- (D) \(\frac{29}{15}\)