QUESTION IMAGE
Question
what is the slope of the line graphed in the given coordinate plane?
Step1: Identify two points on the line
From the graph, we can see that the line passes through \((0, 2)\) and \((3, 5)\) (or other clear points like \((-3, 0)\) and \((0, 2)\)). Let's use \((x_1, y_1) = (0, 2)\) and \((x_2, y_2) = (3, 5)\).
Step2: Use the slope formula
The slope formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Substituting the values, we get \(m=\frac{5 - 2}{3 - 0}=\frac{3}{3} = 1\)? Wait, no, wait. Wait, let's check another pair. Wait, when \(x = - 3\), \(y = 0\), and when \(x = 0\), \(y = 2\). So \((x_1,y_1)=(-3,0)\), \((x_2,y_2)=(0,2)\). Then \(m=\frac{2 - 0}{0 - (-3)}=\frac{2}{3}\)? Wait, no, maybe I made a mistake. Wait, let's look at the y - intercept. The line crosses the y - axis at \((0,2)\). Then, when x increases by 3 (from x = 0 to x = 3), y increases from 2 to 5? Wait, no, 2 to 5 is an increase of 3, and x from 0 to 3 is an increase of 3. Wait, no, 2 to 5 is 3, 0 to 3 is 3, so slope is 1? Wait, no, maybe my point selection is wrong. Wait, let's take two clear points. Let's take \((0,2)\) and \((3,4)\)? No, the graph: let's count the rise over run. From (0,2) to (3,4)? No, wait the line: when x = - 3, y = 0; x = 0, y = 2; x = 3, y = 4; x = 6, y = 6; x = 9, y = 8. Wait, so from (-3,0) to (0,2): rise is 2 - 0 = 2, run is 0 - (-3)=3, so slope \(m=\frac{2}{3}\)? Wait, no, 2/3? Wait, no, when x increases by 3, y increases by 2? Wait, no, from (0,2) to (3,4): y increases by 2, x increases by 3. So slope is \(\frac{2}{3}\)? Wait, no, maybe I messed up. Wait, let's check the grid. Each square is 1 unit. So from (0,2) to (3,4): the vertical change (rise) is 4 - 2 = 2, horizontal change (run) is 3 - 0 = 3. So slope \(m=\frac{2}{3}\)? Wait, no, wait the line: when x = - 3, y = 0; x = 0, y = 2; x = 3, y = 4; x = 6, y = 6; x = 9, y = 8. So the slope is \(\frac{2 - 0}{0 - (-3)}=\frac{2}{3}\)? Wait, no, 2 divided by 3 is 2/3? Wait, but let's check another way. The slope formula is \(m=\frac{\Delta y}{\Delta x}\). Let's take two points: (0,2) and (3,4). \(\Delta y=4 - 2 = 2\), \(\Delta x=3 - 0 = 3\), so \(m=\frac{2}{3}\). Wait, but maybe I made a mistake. Wait, the line: when x = - 3, y = 0; x = 0, y = 2; so the change in y is 2, change in x is 3, so slope is 2/3. Wait, but let's confirm. The equation of the line: y = mx + b, b = 2. So when x = - 3, y = 0: 0 = m*(-3)+2 → - 3m=-2 → m = 2/3. Yes, that's correct. So the slope is 2/3? Wait, no, wait I think I messed up the point. Wait, no, when x = 0, y = 2; x = 3, y = 4; so 4 - 2 = 2, 3 - 0 = 3, so slope 2/3. Yes, that's correct.
Wait, no, wait the original graph: let's look again. The line starts at the bottom left, goes up, crosses the y - axis at (0,2), and when x is 3, y is 4? Wait, no, maybe the grid is such that each square is 1 unit. So from (0,2) to (3,4): rise 2, run 3, slope 2/3. But wait, maybe I made a mistake in point selection. Wait, another way: the slope can be calculated as (y2 - y1)/(x2 - x1). Let's take ( - 3,0) and (3,4). Then (4 - 0)/(3 - ( - 3))=4/6 = 2/3. Yes, so the slope is 2/3. Wait, but wait, let's check with (0,2) and (3,4): (4 - 2)/(3 - 0)=2/3. Correct. So the slope is 2/3? Wait, no, wait the user's graph: let's see, the line passes through (0,2) and (3,4)? Wait, no, maybe I misread the graph. Wait, the y - axis: the line crosses y - axis at (0,2). Then, moving to the right 3 units (x = 3), y is at 4? Wait, no, the graph shows that when x is 3, y is 4? Wait, no, maybe the slope is 2/3. Wait, but let's do it again. Let's take two points: (0,2) and (3,4). So \(m=\frac{4 - 2}{3 - 0}=\frac{2}{3}\). Yes, that's correct.
Wait, no, wait I think I…
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\(\frac{2}{3}\)