Question

what is the product of $d - 9$ and $2d^2 + 11d - 4$?\
$\circ\\ 2d^3 - 7d^2 - 103d + 36$\
$\circ\\ 2d^3 - 7d^2 - 95d + 36$\
$\circ\\ 2d^3 + 7d^2 - 95d + 36$\
$\circ\\ 2d^3 + 7d^2 - 103d + 36$

Explanation:

Step1: Distribute $d$ to each term

$d \times 2d^2 + d \times 11d + d \times (-4) = 2d^3 + 11d^2 - 4d$

Step2: Distribute $-9$ to each term

$-9 \times 2d^2 + (-9) \times 11d + (-9) \times (-4) = -18d^2 - 99d + 36$

Step3: Combine all resulting terms

$2d^3 + 11d^2 - 4d - 18d^2 - 99d + 36$

Step4: Combine like terms

$2d^3 + (11d^2 - 18d^2) + (-4d - 99d) + 36 = 2d^3 -7d^2 -103d +36$

Answer:

$2d^3 - 7d^2 - 103d + 36$