Question

what is the probability that both spinners will land on 2?
\\(\frac{1}{12}\\)
\\(\frac{1}{6}\\)
\\(\frac{1}{4}\\)
\\(\frac{1}{3}\\)

Explanation:

Step1: Find probability of first spinner landing on 2

The first spinner is divided into 3 equal - sized sections. The probability of landing on 2 is $\frac{1}{3}$ since there is 1 section labeled 2 out of 3 total sections.

Step2: Find probability of second spinner landing on 2

The second spinner is divided into 4 equal - sized sections. The probability of landing on 2 is $\frac{1}{4}$ since there is 1 section labeled 2 out of 4 total sections.

Step3: Use multiplication rule for independent events

Since the spins of the two spinners are independent events, the probability that both spinners land on 2 is the product of their individual probabilities. So, $P=\frac{1}{3}\times\frac{1}{4}=\frac{1}{12}$.

Answer:

$\frac{1}{12}$