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what is ( moverarc{hi} )? there is a circle with center at the intersec…

Question

what is ( moverarc{hi} )?
there is a circle with center at the intersection of several radii. points on the circle are g, h, i, f. the arc from g to h is 60°, from g to f is 130°, from f to i is 70°. we need to find ( moverarc{hi} ).

Explanation:

Step1: Recall circle angle sum

A full circle is \(360^\circ\). Sum of all arcs equals \(360^\circ\).

Step2: Sum known arcs

Known arcs: \(60^\circ\) (G to H), \(130^\circ\) (G to F), \(70^\circ\) (F to I). Sum: \(60 + 130 + 70 = 260^\circ\).

Step3: Calculate arc HI

Subtract sum from \(360^\circ\): \(360 - 260 = 100^\circ\).

Answer:

\(100\)