Question

what is $10 \times \frac{11}{12}$?
mixed number
fraction
whole number
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Explanation:

Step1: Multiply the whole number by the fraction

To calculate \( 10\times\frac{11}{12} \), we multiply the numerator of the fraction by the whole number: \( 10\times11 = 110 \), so we get \( \frac{110}{12} \).

Step2: Simplify the fraction

Simplify \( \frac{110}{12} \) by dividing numerator and denominator by their greatest common divisor, which is 2. So \( \frac{110\div2}{12\div2}=\frac{55}{6} \).

Step3: Convert to a mixed number

Divide 55 by 6. \( 6\times9 = 54 \), so \( 55 = 6\times9+1 \). Thus, \( \frac{55}{6}=9\frac{1}{6} \). But looking at the given mixed number format with 1 as the whole number part (maybe a typo or mis - formatting in the problem display), if we consider the calculation as \( 10\times\frac{11}{12}=\frac{110}{12}=\frac{55}{6}=9\frac{1}{6} \), but if we assume the whole number part is 9 (maybe the 1 in the box is a mistake), and the fraction part is \( \frac{1}{6} \). Wait, maybe the problem has a different approach. Let's re - calculate: \( 10\times\frac{11}{12}=\frac{10\times11}{12}=\frac{110}{12}=\frac{55}{6}=9\frac{1}{6} \). But the given mixed number has 1 as the whole number. Maybe there is a mistake, but following the steps:
First, \( 10\times\frac{11}{12}=\frac{110}{12}=\frac{55}{6} \). Converting to mixed number: \( 55\div6 = 9\) with a remainder of 1, so \( 9\frac{1}{6} \). But if we consider the given box with 1 as the whole number, maybe it's a different calculation. Wait, maybe the problem is \( 1\times\frac{11}{12} \)? No, the problem says 10. Anyway, proceeding with the correct calculation:
\( 10\times\frac{11}{12}=\frac{110}{12}=\frac{55}{6}=9\frac{1}{6} \). But if we look at the boxes, the whole number part, numerator, and denominator. So the mixed number is \( 9\frac{1}{6} \), but if the first box is 9 (maybe the 1 is a typo), numerator 1, denominator 6.

Answer:

The mixed number is \( 9\frac{1}{6} \), so the whole number part is 9, numerator is 1, denominator is 6. (Assuming the 1 in the first box is a typo and should be 9)