Question

what is the measure of this angle?
\\( m\angle abc = ?^\circ \\)

Explanation:

Identify the initial ray

$$ \text{Ray } BC \text{ points to } 0^\circ $$

Identify the terminal ray

$$ \text{Ray } BA \text{ points to } 40^\circ $$

Calculate the angle measure

$$ \text{m}\angle ABC = 40^\circ - 0^\circ = 40^\circ $$

Answer:

What is the measure of this angle?

\(\text{m}\angle ABC =\) <blank>\(40\)</blank>\(^\circ\)