QUESTION IMAGE
Question
- what is the density of 180 grams of methanol whose volume is 600 cm³?
- what is the density of a piece of wood that has a mass of 25 grams and a volume of 29.4 cm³?
- what is the density of 450 grams of gas that has a volume of 680 - ml?
- a piece of aluminum has a volume of 90 - ml and a total mass of 244 grams. what is the density of the aluminum?
- a rock has a density of 35 g/ml and a mass of 15 grams. what is the rocks volume?
- a block has a mass of 10 grams and a 50 g/cm³. what is the blocks volume?
- a pencil has a density of 2 g/ml and a volume of 1.5 - ml. what is the pencils mass?
- jeff has a density of 1000 g/ml and a volume of 25 - ml. what is jeffs mass?
Step1: Rappel de la formule de densité
La densité $
ho$ est donnée par $
ho=\frac{m}{V}$, où $m$ est la masse et $V$ le volume.
Step2: Résolution de la question 1
Pour le méthanol, $m = 180\ g$ et $V=600\ cm^{3}$. En utilisant la formule $
ho=\frac{m}{V}$, on a $
ho=\frac{180\ g}{600\ cm^{3}} = 0.3\ g/cm^{3}$.
Step3: Résolution de la question 2
Pour le bois, $m = 25\ g$ et $V = 29.4\ cm^{3}$. Alors $
ho=\frac{25\ g}{29.4\ cm^{3}}\approx0.85\ g/cm^{3}$.
Step4: Résolution de la question 3
Pour le gaz, $m = 450\ g$ et $V = 680\ mL$. Donc $
ho=\frac{450\ g}{680\ mL}\approx0.66\ g/mL$.
Step5: Résolution de la question 4
Pour l'aluminium, $m = 244\ g$ et $V = 90\ mL$. Ainsi $
ho=\frac{244\ g}{90\ mL}\approx2.71\ g/mL$.
Step6: Résolution de la question 5
On connaît $
ho = 35\ g/mL$ et $m = 15\ g$. En utilisant la formule $V=\frac{m}{
ho}$, on obtient $V=\frac{15\ g}{35\ g/mL}\approx0.43\ mL$.
Step7: Résolution de la question 6
On a $m = 10\ g$ et $
ho = 50\ g/cm^{3}$. Alors $V=\frac{m}{
ho}=\frac{10\ g}{50\ g/cm^{3}} = 0.2\ cm^{3}$.
Step8: Résolution de la question 7
On a $
ho = 2\ g/mL$ et $V = 1.5\ mL$. En utilisant $m=
ho\times V$, on trouve $m=2\ g/mL\times1.5\ mL = 3\ g$.
Step9: Résolution de la question 8
On a $
ho = 1000\ g/mL$ et $V = 25\ mL$. Donc $m=
ho\times V=1000\ g/mL\times25\ mL = 25000\ g$.
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- $0.3\ g/cm^{3}$
- $\approx0.85\ g/cm^{3}$
- $\approx0.66\ g/mL$
- $\approx2.71\ g/mL$
- $\approx0.43\ mL$
- $0.2\ cm^{3}$
- $3\ g$
- $25000\ g$