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what is the corresponding point for t? t ( -2, -4 )

Question

what is the corresponding point for t?
t ( -2, -4 )

Explanation:

Step1: Identify T's original coordinates

Looking at the grid, point T is at \( (-2, -4) \)? Wait, no, wait. Wait, let's check the grid. Wait, the original T: let's see the x - coordinate and y - coordinate. Wait, the grid lines: each square is 1 unit. Let's find the original T. Wait, the figure: T is at \( (-2, -4) \)? Wait, no, wait, the problem is about finding the corresponding point? Wait, maybe there's a translation. Wait, looking at point V and V': V is at, say, (-8, -5)? Wait, no, V is at (-8, -5)? Wait, V' is at (8, -5). So the translation vector is (16, 0)? Wait, no, V is at (-8, -5), V' is at (8, -5). So the change in x is 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, maybe it's a reflection or translation. Wait, alternatively, let's check the original T. Wait, the original T: looking at the grid, T is at (-2, -4)? Wait, no, wait, the blue triangle: T is at (-2, -4)? Wait, no, let's count the x - axis: from the origin (0,0), moving left 2 units (x=-2) and down 4 units (y = - 4). Wait, but if we look at the transformation of V to V': V is at (-8, -5), V' is at (8, -5). So the translation is (16, 0)? No, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, maybe it's a horizontal translation. Wait, V is at x=-8, V' at x = 8. So the translation vector is (16, 0)? Wait, no, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, maybe the translation is 10 units? Wait, no, let's check the x - coordinate of S: S is at (-7, -3). Wait, maybe I made a mistake. Wait, the problem is "What is the corresponding point for T?" So maybe the figure is translated. Let's find the original coordinates of T. Let's look at the grid: T is at (x, y). Let's count the x - axis: from 0, moving left 2 units (x=-2), y - axis: moving down 4 units (y=-4). Wait, but if we look at the transformation of V to V': V is at (-8, -5), V' is at (8, -5). So the translation is (16, 0)? No, 8 - (-8)=16? Wait, no, 8 - (-8)=16? Wait, maybe it's a reflection over the y - axis? Wait, reflection over y - axis changes (x,y) to (-x,y). Wait, no, V is at (-8, -5), V' is at (8, -5). So reflection over y - axis: (-x,y)→(x,y). So if T is at (-2, -4), then its corresponding point (after reflection over y - axis) would be (2, -4)? Wait, no, that doesn't match V. Wait, V is at (-8, -5), V' is at (8, -5). So the x - coordinate changes from -8 to 8, so the transformation is (x,y)→(-x,y)? No, -8 to 8 is x→-x? Wait, -(-8)=8. Yes! So it's a reflection over the y - axis. So the rule is (x, y)→(-x, y). So for point T, which is at (-2, -4), applying the reflection over y - axis: x becomes -(-2)=2, y remains -4. Wait, but that doesn't match V. Wait, V is at (-8, -5), reflection over y - axis is (8, -5), which is V'. So yes, reflection over y - axis: (x,y)→(-x,y). So original T: let's find T's original coordinates. Wait, looking at the grid, T is at (-2, -4)? Wait, no, wait, the x - coordinate of T: let's count from the origin. The vertical line through T: x=-2, horizontal line: y=-4. So T is (-2, -4). Then reflecting over y - axis, the corresponding point T' would be (2, -4)? Wait, no, that can't be. Wait, maybe I made a mistake in T's original coordinates. Wait, let's look again. The blue triangle: T is at ( - 2, - 4)? Wait, no, the x - axis: from 0, moving left 2 units (x=-2), y - axis: moving down 4 units (y=-4). Then, if the transformation is reflection over y - axis, then T' would be (2, -4). But wait, let's check V: V is at (-8, -5), reflection over y - axis is (8, -5), which is V'. So yes, reflection over y - axis. So for T(-2, -4), refle…

Answer:

\( (2, -4) \)