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what is the axis of symmetry for this quadratic function? f(x)=-4x^2 + …

Question

what is the axis of symmetry for this quadratic function? f(x)=-4x^2 + 16x + 47 x = ? axis of symmetry: x = -\frac{b}{2a} simplify your answer completely.

Explanation:

Step1: Identify a and b

For \( f(x) = -4x^2 + 16x + 47 \), \( a=-4 \), \( b=16 \)

Step2: Apply axis formula

\( x = -\frac{b}{2a} = -\frac{16}{2\times(-4)} \)

Step3: Simplify calculation

\( x = -\frac{16}{-8} = 2 \)

Answer:

2