Question

what is the area of a parallelogram formed by $v_1 = \langle 2,6\
angle$ and $v_2 = \langle 3,1\
angle$?
2 square units
6 square units
16 square units
20 square units

Explanation:

Step1: Recall the formula for the area of a parallelogram formed by vectors

If \(\vec{v}=\langle a,b
angle\) and \(\vec{w}=\langle c,d
angle\), the area \(A = |ad - bc|\).
Here, \(\vec{v}=\langle2,6
angle\) (so \(a = 2\), \(b = 6\)) and \(\vec{w}=\langle3,1
angle\) (so \(c = 3\), \(d = 1\)).

Step2: Substitute the values into the formula

$$
LATEXBLOCK0
$$

Answer:

\(16\) square units (the third option)