QUESTION IMAGE
Question
what is the area of the original triangle? square units
Step1: Calculate the area of the rectangle
Assume the grid has unit - length squares. The rectangle that encloses the triangle (by completing the figure) has length \(l = 5\) units and width \(w=3\) units. The area of a rectangle \(A_{rect}=l\times w\), so \(A_{rect}=5\times3 = 15\) square units.
Step2: Calculate the area of the non - blue regions
There are three non - blue right - angled triangles.
- The first non - blue triangle has base \(b_1 = 3\) units and height \(h_1=1\) unit. The area of a right - angled triangle \(A=\frac{1}{2}bh\), so \(A_1=\frac{1}{2}\times3\times1=\frac{3}{2}\) square units.
- The second non - blue triangle has base \(b_2 = 5\) units and height \(h_2 = 2\) units. So \(A_2=\frac{1}{2}\times5\times2 = 5\) square units.
- The third non - blue triangle has base \(b_3=2\) units and height \(h_3 = 2\) units. So \(A_3=\frac{1}{2}\times2\times2=2\) square units.
The total area of the non - blue regions \(A_{non - blue}=A_1 + A_2+A_3=\frac{3}{2}+5 + 2=\frac{3 + 10+4}{2}=\frac{17}{2}=8.5\) square units.
Step3: Calculate the area of the blue triangle
The area of the blue triangle \(A_{triangle}=A_{rect}-A_{non - blue}\). So \(A_{triangle}=15-8.5 = 6.5\) square units.
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\(6.5\)