Question

b warm up (day 2)
find the area and perimeter/circumference
round to the nearest tenth, if necessary.
3.6 ft 2.8 ft
4.5 in
p=
a≈
c≈14.13
a≈99.82
14.1

Explanation:

Step1: Identify the shape of the table

The table is a rectangle with length $l = 3.6$ ft and width $w=2.8$ ft.

Step2: Calculate the perimeter of the rectangle

The formula for the perimeter of a rectangle is $P = 2(l + w)$. Substitute $l = 3.6$ ft and $w = 2.8$ ft into the formula: $P=2(3.6 + 2.8)=2\times6.4 = 12.8$ ft.

Step3: Calculate the area of the rectangle

The formula for the area of a rectangle is $A=l\times w$. Substitute $l = 3.6$ ft and $w = 2.8$ ft into the formula: $A=3.6\times2.8 = 10.08\approx10.1$ ft².

Step4: Identify the shape of the clock

The clock is a circle with diameter $d = 4.5$ in.

Step5: Calculate the circumference of the circle

The formula for the circumference of a circle is $C=\pi d$. Substitute $d = 4.5$ in into the formula: $C=\pi\times4.5\approx3.14\times4.5 = 14.13\approx14.1$ in.

Step6: Calculate the area of the circle

The formula for the area of a circle is $A=\pi(\frac{d}{2})^2$. First, find the radius $r=\frac{d}{2}=\frac{4.5}{2}=2.25$ in. Then $A=\pi\times(2.25)^2\approx3.14\times5.0625 = 15.89625\approx15.9$ in².

Answer:

For the table:
$P = 12.8$ ft
$A\approx10.1$ ft²
For the clock:
$C\approx14.1$ in
$A\approx15.9$ in²