Question

volume of a cone level 1
score:9/15 penalty:1 off
question
find the volume of a right circular cone that has a height of 3.5 ft and a base with a radius of 18.9 ft. round your answer to the nearest tenth of a cubic foot.
answer attempt 1 out of 2
ft³
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Explanation:

Step1: Recall the volume formula for a cone

The volume \( V \) of a right circular cone is given by the formula \( V=\frac{1}{3}\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cone.

Step2: Substitute the given values

We are given that \( r = 18.9\space\text{ft} \) and \( h=3.5\space\text{ft} \). Substitute these values into the formula:
\( V=\frac{1}{3}\times\pi\times(18.9)^{2}\times3.5 \)
First, calculate \( (18.9)^{2}=18.9\times18.9 = 357.21 \)
Then, \( \frac{1}{3}\times357.21\times3.5=\frac{357.21\times3.5}{3} \)
\( 357.21\times3.5 = 1250.235 \)
\( \frac{1250.235}{3}=416.745 \)
Now, multiply by \( \pi \) (using \( \pi\approx3.14159 \)):
\( V = 416.745\times3.14159\approx1309.0 \) (rounded to the nearest tenth)

Answer:

\( 1309.0 \)