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Question
vasquez unit 5
- what additional congruence must be established to prove \\( \triangle c a t \cong \triangle s a t \\) by hl?
- what additional congruence must be established to prove \\( \triangle t i e \cong \triangle m e i \\) by aas?
3.
Step1: Recall HL (Hypotenuse - Leg) theorem
HL theorem states that for right - angled triangles, if the hypotenuse and one leg of a right - triangle are congruent to the hypotenuse and one leg of another right - triangle, then the two right - triangles are congruent. In \(\triangle CAT\) and \(\triangle SAT\), \(\angle CTA=\angle STA = 90^{\circ}\) (right angles) and \(AT\) is a common leg (\(AT\cong AT\)).
Step2: Identify the hypotenuse
The hypotenuses of \(\triangle CAT\) and \(\triangle SAT\) are \(CA\) and \(SA\) respectively. So, we need \(CA\cong SA\) to prove \(\triangle CAT\cong\triangle SAT\) by HL.
4.
Step1: Recall AAS (Angle - Angle - Side) theorem
AAS theorem states that if two angles and a non - included side of one triangle are congruent to two angles and the corresponding non - included side of another triangle, then the two triangles are congruent. In \(\triangle TIE\) and \(\triangle MEI\), \(\angle TIE=\angle MEI\) (given by the mark) and \(\angle IET=\angle IEM\) (given by the mark).
Step2: Identify the non - included side
The non - included sides for the pairs of angles are \(TE\) and \(MI\). So, we need \(TE\cong MI\) to prove \(\triangle TIE\cong\triangle MEI\) by AAS.
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- \(CA\cong SA\)
- \(TE\cong MI\)