Question

using trig to find a side
score 0/2 penalty none
question
solve for x. round to the nearest tenth, if necessary.
answer attempt 1 out of 2
x =

Explanation:

Step1: Identify the trigonometric ratio

In right - triangle \( \triangle NOM\), we know an angle (\(25^{\circ}\)) and the adjacent side (\(ON = 6.3\)) and we want to find the hypotenuse (\(OM=x\)). The cosine ratio is defined as \( \cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). So, \( \cos(25^{\circ})=\frac{6.3}{x}\).

Step2: Solve for \(x\)

Rearrange the formula \(x=\frac{6.3}{\cos(25^{\circ})}\).
We know that \( \cos(25^{\circ})\approx0.9063\).
Then \(x=\frac{6.3}{0.9063}\approx6.95\approx7.0\)

Answer:

\(7.0\)