Question

1. using ohms law, solve for vo at tp1. a 12 v b 8 v c 3 v d 2 v

Explanation:

Step1: Calculate total resistance

The resistors are in series. $R_{total}=R1 + R2+R3=2k\Omega + 4k\Omega+2k\Omega = 8k\Omega$

Step2: Calculate total current using Ohm's Law

$I=\frac{V}{R_{total}}$, where $V = 12V$ and $R_{total}=8k\Omega$. So $I=\frac{12V}{8k\Omega}=1.5mA$

Step3: Calculate voltage across R1 and R2

The voltage across R1 and R2 together is $V_{R1 + R2}=I\times(R1 + R2)$. Substituting $I = 1.5mA$, $R1=2k\Omega$ and $R2 = 4k\Omega$, we get $V_{R1 + R2}=1.5mA\times(2k\Omega + 4k\Omega)=9V$

Step4: Calculate voltage at TP1

The voltage at TP1 is the voltage across R1 and R2. So $V_o=9V$

However, if we assume TP1 is the voltage across R1 only:

Step1: Calculate total resistance

$R_{total}=R1 + R2+R3=2k\Omega + 4k\Omega+2k\Omega = 8k\Omega$

Step2: Calculate total current using Ohm's Law

$I=\frac{V}{R_{total}}$, with $V = 12V$ and $R_{total}=8k\Omega$, so $I=\frac{12V}{8k\Omega}=1.5mA$

Step3: Calculate voltage across R1

Using Ohm's Law $V = IR$, for $R = R1=2k\Omega$ and $I = 1.5mA$, we have $V_o=I\times R1=1.5mA\times2k\Omega = 3V$

Answer:

C. 3V