Question

use the order of operations to find the value of the following expression.
$4^2 - 32 \div 4^2 \times 2 - 3$

$4^2 - 32 \div 4^2 \times 2 - 3 = \square$

Explanation:

Step1: Calculate exponents

First, we handle the exponentiation. We have \(4^2\) and \(4^2\) in the expression. \(4^2 = 16\), so the expression becomes \(16 - 32\div16\times2 - 3\).

Step2: Perform division

Next, we do the division operation. \(32\div16 = 2\), so now the expression is \(16 - 2\times2 - 3\).

Step3: Perform multiplication

Then, we perform the multiplication. \(2\times2 = 4\), so the expression becomes \(16 - 4 - 3\).

Step4: Perform subtraction from left to right

First, \(16 - 4 = 12\), and then \(12 - 3 = 9\).

Answer:

\(9\)