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use the given data to find the equation of the regression line. examine…

Question

use the given data to find the equation of the regression line. examine the scatterplot and identify a characteristic the data that is ignored by the regression line.
x 9 4 7 10 6 13 5 11 8 14 12
y 8.81 1.55 7.04 9.11 5.60 7.76 3.76 9.04 8.11 6.55 8.60
ŷ = □ + □x (round to two decimal places as needed.)

Explanation:

Step1: Calculate necessary sums

First, we need to calculate \( \sum x \), \( \sum y \), \( \sum xy \), and \( \sum x^2 \) for the given data.
The data points are:
\( x: 9, 4, 7, 10, 6, 13, 5, 11, 8, 14, 12 \)
\( y: 8.81, 1.55, 7.04, 9.11, 5.60, 7.76, 3.76, 9.04, 8.11, 6.55, 8.60 \)

Calculating \( \sum x \):
\( \sum x = 9 + 4 + 7 + 10 + 6 + 13 + 5 + 11 + 8 + 14 + 12 = 99 \)

Calculating \( \sum y \):
\( \sum y = 8.81 + 1.55 + 7.04 + 9.11 + 5.60 + 7.76 + 3.76 + 9.04 + 8.11 + 6.55 + 8.60 = 76.93 \)

Calculating \( \sum xy \):
\( (9\times8.81) + (4\times1.55) + (7\times7.04) + (10\times9.11) + (6\times5.60) + (13\times7.76) + (5\times3.76) + (11\times9.04) + (8\times8.11) + (14\times6.55) + (12\times8.60) \)
\( = 79.29 + 6.2 + 49.28 + 91.1 + 33.6 + 100.88 + 18.8 + 99.44 + 64.88 + 91.7 + 103.2 \)
\( = 748.37 \)

Calculating \( \sum x^2 \):
\( 9^2 + 4^2 + 7^2 + 10^2 + 6^2 + 13^2 + 5^2 + 11^2 + 8^2 + 14^2 + 12^2 \)
\( = 81 + 16 + 49 + 100 + 36 + 169 + 25 + 121 + 64 + 196 + 144 \)
\( = 949 \)

Step2: Calculate the slope \( b \)

The formula for the slope \( b \) of the regression line is:
\( b = \frac{n\sum xy - \sum x \sum y}{n\sum x^2 - (\sum x)^2} \)
where \( n = 11 \) (number of data points)

Substituting the values:
\( n\sum xy = 11\times748.37 = 8232.07 \)
\( \sum x \sum y = 99\times76.93 = 7616.07 \)
\( n\sum x^2 = 11\times949 = 10439 \)
\( (\sum x)^2 = 99^2 = 9801 \)

\( b = \frac{8232.07 - 7616.07}{10439 - 9801} = \frac{616}{638} \approx 0.9655 \approx 0.97 \) (rounded to two decimal places)

Step3: Calculate the y-intercept \( a \)

The formula for the y-intercept \( a \) is:
\( a = \bar{y} - b\bar{x} \)
where \( \bar{x} = \frac{\sum x}{n} = \frac{99}{11} = 9 \)
\( \bar{y} = \frac{\sum y}{n} = \frac{76.93}{11} \approx 6.9936 \)

Substituting the values:
\( a = 6.9936 - 0.9655\times9 \)
\( = 6.9936 - 8.6895 \)
\( = -1.6959 \approx -1.70 \) (rounded to two decimal places)

Answer:

\( \hat{y} = -1.70 + 0.97x \)