Question

use the data in the following table, which lists drive - thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.

drive - thru restaurant

	a	b	c	d
order not accurate	31	58	37	15

if one order is selected, find the probability of getting food that is not from restaurant a.

the probability of getting food that is not from restaurant a is
(round to three decimal places as needed.)

Explanation:

Step1: Calculate total orders

First, we find the total number of orders by summing up all the values in the table. For Restaurant A: \(323 + 31 = 354\). For Restaurant B: \(273 + 58 = 331\). For Restaurant C: \(235 + 37 = 272\). For Restaurant D: \(135 + 15 = 150\). Then total orders \(= 354 + 331 + 272 + 150\). Let's calculate that: \(354+331 = 685\), \(685+272 = 957\), \(957+150 = 1107\).

Step2: Calculate orders not from A

Orders from A are 354, so orders not from A are total orders minus orders from A: \(1107 - 354 = 753\).

Step3: Calculate probability

Probability is number of favorable outcomes (not from A) divided by total outcomes. So probability \(= \frac{753}{1107}\). Let's compute that: \(753\div1107\approx0.680\) (rounded to three decimal places).

Answer:

\(0.680\)