Question

use the accompanying radiation levels (in \\( \frac { w } { k g } \\) ) for 50 different cell phones. find the percentile corresponding to \\( 1.31 \frac { w } { k g } \\).
click the icon to view the radiation levels.
the percentile corresponding to \\( 1.31 \frac { w } { k g } \\) is
(round to the nearest whole number as needed.)

Explanation:

Step1: Count the number of values less than or equal to \(1.31\)

Count the number of data points in the list that are less than or equal to \(1.31\). By going through the data:
The first - row data: \(0.24,0.28,0.28,0.47,0.59,0.62,0.65,0.69,0.80,0.86\) (10 values)
The second - row data: \(0.89,0.90,0.91,0.92,0.93,0.96,1.01,1.02,1.10,1.10\) (10 values)
The third - row data: \(1.10,1.12,1.14,1.16,1.17,1.17,1.18,1.18,1.18,1.21\) (10 values)
The fourth - row data: \(1.22,1.23,1.24,1.25,1.26,1.26,1.27,1.28,1.30,1.30\) (10 values)
The fifth - row data: \(1.31\) (1 value)
The number of values less than or equal to \(1.31\) is \(n = 41\)

Step2: Use the percentile formula

The formula for the percentile \(P\) is \(P=\frac{\text{Number of values less than or equal to }x}{\text{Total number of values}}\times100\)
Here, \(x = 1.31\), the total number of values \(N=50\)
Substitute \(n = 41\) and \(N = 50\) into the formula: \(P=\frac{41}{50}\times100\)
\(P = 82\)

Answer:

\(82\)