Question

use the accompanying radiation levels (in \\( \frac { w } { k g } \\) ) for 50 different cell phones. find the percentile corresponding to \\( 1.46 \frac { w } { k g } \\).
click the icon to view the radiation levels.
the percentile corresponding to \\( 1.46 \frac { w } { k g } \\) is
(round to the nearest whole number as needed.)

Explanation:

Step1: Count the number of values less than or equal to \(1.46\)

Count the number of data points in the list that are less than or equal to \(1.46\). By going through the data:
The first - row: \(9\) values.
The second - row: \(10\) values.
The third - row: \(10\) values.
The fourth - row: \(10\) values.
The fifth - row: up to \(1.46\), we have \(4\) values (since the fifth - row is \(1.32\ 1.34\ 1.37\ 1.42\ 1.46\ 1.49\ 1.49\ 1.50\ 1.52\ 1.58\)).
The total number of values less than or equal to \(1.46\) is \(9 + 10+10 + 10+4=43\).

Step2: Use the percentile formula

The formula for the percentile \(P\) is \(P=\frac{\text{Number of values less than or equal to }x}{\text{Total number of values}}\times100\).
Here, \(x = 1.46\), the number of values less than or equal to \(x\) is \(n = 43\), and the total number of values \(N=50\).
Substitute into the formula: \(P=\frac{43}{50}\times100\).
Calculate \(\frac{43}{50}\times100=43\times2 = 86\).

Answer:

\(86\)