Question

use the accompanying radiation levels \\( \frac { w } { k g } \\) for 50 different cell phones. find the percentile corresponding to \\( 1.07 \frac { w } { k g } \\)

the percentile corresponding to \\( 1.07 \frac { w } { k g } \\) is
(round to the nearest whole number as needed.)

Explanation:

Step1: Count the number of values less than \(1.07\)

First, count how many values in the data set are less than \(1.07\).
Looking at the data:
The values less than \(1.07\) are \(0.19,0.25,0.36,0.53,0.55,0.58,0.59,0.70,0.79,0.89,0.90,0.91,0.92,0.93,0.96,0.97,1.00,1.02\).
The number of these values \(n = 18\).

Step2: Calculate the percentile

The formula for the percentile \(P\) is \(P=\frac{\text{Number of values less than }x}{\text{Total number of values}}\times100\).
Here, \(x = 1.07\) and the total number of values \(N=50\).
Substitute \(n = 18\) and \(N = 50\) into the formula: \(P=\frac{18}{50}\times100\).

$$P=\frac{18\times100}{50}= 36$$

Answer:

\(36\)