Question

unit 4 test: graphs and describing distributions multiple choice

1. the average weight of frances large fontaine bullfrog is 2.9 kilograms, with a standard deviation of 1.8 kilograms. your friend wants to know what this is in pounds. find the following: (1 kg = 2.2 pounds)

a. how much is the bullfrogs weight in pounds?

b. how much is the standard deviation in pounds?

round your answers to 2 decimal places!

a. weight in pounds?

b. standard deviation in pounds?

Explanation:

Step1: Convert weight from kg to pounds

Given \(1\) kg \( = 2.2\) pounds. The weight of the bullfrog is \(2.9\) kg.
Multiply the weight in kg by the conversion factor: \(2.9\times2.2\)

$$2.9\times2.2=(3 - 0.1)\times2.2=3\times2.2-0.1\times2.2 = 6.6-0.22=6.38$$

Step2: Convert standard deviation from kg to pounds

The standard deviation is \(1.8\) kg.
Multiply the standard - deviation in kg by the conversion factor: \(1.8\times2.2\)

$$1.8\times2.2=(2 - 0.2)\times2.2=2\times2.2-0.2\times2.2=4.4 - 0.44 = 3.96$$

Answer:

A. \(6.38\)
B. \(3.96\)