Question

unit: radical expressions and quadratic equations progress: the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. approximate \\(\sqrt{56}\\) to the tenths place. the solution is

Explanation:

Step1: Find two perfect squares around 56

We know that $7^2 = 49$ and $8^2 = 64$. So, $\sqrt{49}<\sqrt{56}<\sqrt{64}$, which means $7<\sqrt{56}<8$.

Step2: Calculate the difference

The difference between 56 and 49 is $56 - 49 = 7$. The difference between 64 and 49 is $64 - 49 = 15$.

Step3: Approximate the decimal part

We can approximate the decimal part by $\frac{7}{15}\approx0.47$. So, $\sqrt{56}\approx7 + 0.47 = 7.47$.

Step4: Round to the tenths place

Rounding 7.47 to the tenths place gives 7.5.

Answer:

7.5