Question

type the missing digits:
9 8 □

• 7 □ 3

-------
□ 9 6

Explanation:

Step1: Analyze the units place

In the units place, we have $\square - 3 = 6$. So, the digit in the units place of the minuend (98$\square$) should be $6 + 3 = 9$. So the top number is 989.

Step2: Analyze the tens place

Now, the tens place: we had 8 in the minuend, but we might have borrowed for the units place? Wait, no, in the units place, we had $\square - 3 = 6$, so $\square = 9$, no borrowing here. Wait, now the tens place: 8 - $\square$ = 9? That can't be, so we must have borrowed from the hundreds place. So, 18 - $\square$ = 9, so $\square = 18 - 9 = 9$? Wait, no, wait the minuend is 989, subtrahend is 7$\square$3, difference is $\square$96. Let's check the hundreds place. After borrowing, the hundreds place of the minuend is 9 - 1 = 8. Then 8 - 7 = 1, so the hundreds place of the difference is 1. Now, tens place: we borrowed 1 from the hundreds place, so the tens digit of the minuend becomes 8 + 10 = 18 (because we borrowed 1, so 8 becomes 18 in the tens place for subtraction). Then 18 - $\square$ = 9, so $\square$ (tens digit of subtrahend) is 18 - 9 = 9? Wait, no, let's do it step by step.

Minuend: 9 (hundreds), 8 (tens), $\square$ (units)
Subtrahend: 7 (hundreds), $\square$ (tens), 3 (units)
Difference: $\square$ (hundreds), 9 (tens), 6 (units)

Units place: $\square - 3 = 6$ ⇒ $\square = 6 + 3 = 9$. So minuend is 989.

Now, tens place: We have 8 (tens of minuend) - $\square$ (tens of subtrahend) = 9 (tens of difference). But 8 < 9, so we need to borrow 1 from the hundreds place of the minuend. So, after borrowing, the tens digit of the minuend becomes 8 + 10 = 18. Now, 18 - $\square$ = 9 ⇒ $\square = 18 - 9 = 9$. So the tens digit of the subtrahend is 9.

Hundreds place: The minuend's hundreds digit was 9, but we borrowed 1 for the tens place, so it becomes 9 - 1 = 8. Then 8 - 7 (hundreds digit of subtrahend) = 1 (hundreds digit of difference). So the hundreds digit of the difference is 1.

Let's verify: 989 - 793. 9 - 3 = 6 (units), 8 - 9: can't do, borrow 1 from 9 (hundreds), 18 - 9 = 9 (tens), 9 - 1 - 7 = 1 (hundreds). So 989 - 793 = 196. Perfect.

So the missing digits: top box (units of minuend) is 9, middle box (tens of subtrahend) is 9, bottom box (hundreds of difference) is 1.

Answer:

Top box (units of 98$\square$): 9, Middle box (tens of 7$\square$3): 9, Bottom box (hundreds of $\square$96): 1. So the numbers are:

$$\begin{array}{r} 989 \\ -793 \\ \hline 196 \end{array}$$

So the missing digits are (from top to bottom, left to right in the subtrahend and difference): 9 (top box), 9 (middle box in subtrahend), 1 (bottom box in difference).