Question

a. type the equation in center - radius form. $(x - 3)^{2}+(y - 3)^{2}=4$ (simplify your answer.) b. type the equation in general form. (simplify your answer.)

Explanation:

Step 1: Expand \((x - 3)^2\)

Using the formula \((a - b)^2=a^{2}-2ab + b^{2}\), for \(a = x\) and \(b = 3\), we have \((x - 3)^2=x^{2}-6x + 9\).

Step 2: Expand \((y - 3)^2\)

Using the formula \((a - b)^2=a^{2}-2ab + b^{2}\), for \(a = y\) and \(b = 3\), we have \((y - 3)^2=y^{2}-6y + 9\).

Step 3: Substitute the expansions into the given equation

The given equation is \((x - 3)^2+(y - 3)^2 = 4\). Substituting the expansions:

$$
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$$

Answer:

\(x^{2}+y^{2}-6x - 6y+14 = 0\)