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Question
type the correct answer in the box.
in triangle abc, which side is the longest if these are the measures of the angles?
m∠a = 60°, m∠b = (3x − 2)°, m∠c = (2x + 7)°
side is the longest side.
Step1: Sum of angles in triangle
The sum of the interior angles of a triangle is \(180^\circ\). So, \(m\angle A + m\angle B + m\angle C = 180^\circ\). Substituting the given angles: \(60+(3x - 2)+(2x + 7)=180\).
Step2: Solve for x
Simplify the equation: \(60 + 3x-2 + 2x + 7 = 180\) → \(5x + 65 = 180\) → \(5x=180 - 65 = 115\) → \(x=\frac{115}{5}=23\).
Step3: Find measures of angles B and C
For \(m\angle B\): \(3x - 2=3\times23 - 2 = 69 - 2 = 67^\circ\). For \(m\angle C\): \(2x + 7=2\times23+7 = 46 + 7 = 53^\circ\).
Step4: Determine largest angle
Compare the angles: \(m\angle A = 60^\circ\), \(m\angle B = 67^\circ\), \(m\angle C = 53^\circ\). The largest angle is \(\angle B\) (67°).
Step5: Relate angle to side
In a triangle, the longest side is opposite the largest angle. The side opposite \(\angle B\) is \(AC\) (since in triangle \(ABC\), side opposite \(\angle B\) is \(AC\)). Wait, correction: Wait, in triangle \(ABC\), side opposite \(\angle A\) is \(BC\), opposite \(\angle B\) is \(AC\)? No, wait: vertex \(A\) is opposite side \(BC\), vertex \(B\) is opposite side \(AC\)? No, wait, standard notation: in triangle \(ABC\), side \(a\) is opposite \(\angle A\) (BC), side \(b\) opposite \(\angle B\) (AC), side \(c\) opposite \(\angle C\) (AB). Wait, no, actually, side opposite \(\angle A\) is \(BC\), opposite \(\angle B\) is \(AC\)? Wait, no, let's recall: in triangle \(ABC\), angle \(A\) is at vertex \(A\), between sides \(AB\) and \(AC\), so the side opposite angle \(A\) is \(BC\). Angle \(B\) is at vertex \(B\), between sides \(AB\) and \(BC\), so side opposite is \(AC\). Angle \(C\) is at vertex \(C\), between sides \(AC\) and \(BC\), so side opposite is \(AB\). Wait, but the largest angle is \(\angle B\) (67°), so the side opposite \(\angle B\) is \(AC\)? Wait, no, wait, I think I messed up. Wait, angle \(B\) is at vertex \(B\), so the side opposite angle \(B\) is \(AC\)? Wait, no, let's label the triangle: vertices \(A\), \(B\), \(C\). Side opposite \(A\): \(BC\) (length \(a\)), opposite \(B\): \(AC\) (length \(b\)), opposite \(C\): \(AB\) (length \(c\)). So if \(\angle B\) is the largest angle, then the side opposite \(\angle B\) is \(AC\)? Wait, no, wait, the largest angle is \(\angle B\) (67°), so the side opposite \(\angle B\) is \(AC\)? Wait, no, wait, let's recalculate angles again. Wait, \(x = 23\), so angle \(B\): \(3*23 - 2 = 67\), angle \(C\): \(2*23 +7=53\), angle \(A = 60\). So largest angle is \(B\) (67°). So side opposite angle \(B\) is \(AC\)? Wait, no, in triangle \(ABC\), side opposite angle \(B\) is \(AC\)? Wait, no, vertex \(B\) is connected to \(A\) and \(C\), so the side opposite \(B\) is \(AC\). Wait, but maybe I made a mistake in notation. Wait, actually, in triangle \(ABC\), the side opposite angle \(A\) is \(BC\), opposite angle \(B\) is \(AC\), opposite angle \(C\) is \(AB\). So if angle \(B\) is the largest, then side \(AC\) (opposite angle \(B\)) is the longest? Wait, no, wait, no: wait, angle \(B\) is at vertex \(B\), so the side opposite angle \(B\) is \(AC\). Wait, but let's check again. Wait, the angles: angle \(A = 60\), angle \(B = 67\), angle \(C = 53\). So the largest angle is \(B\), so the side opposite \(B\) is \(AC\)? Wait, no, maybe I mixed up. Wait, no, in triangle notation, side \(a\) is BC (opposite A), side \(b\) is AC (opposite B), side \(c\) is AB (opposite C). So if angle B is the largest, then side \(b\) (AC) is the longest? Wait, but maybe the question expects the side opposite the largest angle. Wait, but let's re-express: the largest angle is \(\angle B\), so the si…
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