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Question
6.4 trinomials where a does not equal
(1 point)
factor:
$5x^2 + 5x - 60 = \square$
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Step1: Factor out the greatest common factor
The greatest common factor of \(5x^{2}\), \(5x\) and \(-60\) is \(5\).
$$5x^{2}+5x - 60=5(x^{2}+x - 12)$$
Step2: Factor the quadratic trinomial \(x^{2}+x - 12\)
We need to find two numbers \(m\) and \(n\) such that \(m + n=1\) and \(m\times n=- 12\). The numbers are \(4\) and \(-3\) since \(4+( - 3)=1\) and \(4\times(-3)=-12\).
$$x^{2}+x - 12=(x + 4)(x-3)$$
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\(5(x + 4)(x - 3)\)