QUESTION IMAGE
Question
triangles abc and def have the following characteristics:
∠b and ∠e are right angles
∠a ≅ ∠d
bc ≅ ef
which congruence theorem can be used to prove △abc ≅ △def?
asa
hl
aas
sas
Brief Explanations
- AAS (Angle - Angle - Side):
- We know that \(\angle B=\angle E = 90^{\circ}\) (right angles), \(\angle A=\angle D\) (given), and \(BC = EF\) (given).
- In the AAS congruence theorem, if two angles and a non - included side of one triangle are equal to the corresponding two angles and non - included side of another triangle, then the two triangles are congruent. Here, the non - included side with respect to the two given angles (\(\angle A\) and \(\angle B\) in \(\triangle ABC\), \(\angle D\) and \(\angle E\) in \(\triangle DEF\)) is \(BC\) (in \(\triangle ABC\)) and \(EF\) (in \(\triangle DEF\)) and they are equal.
- Why not other theorems:
- ASA (Angle - Side - Angle): For ASA, the side should be included between the two angles. Here, if we consider the angles \(\angle A\) and \(\angle B\) in \(\triangle ABC\) (and \(\angle D\) and \(\angle E\) in \(\triangle DEF\)), the side \(BC\) (\(EF\)) is not included between \(\angle A\) and \(\angle B\) (\(\angle D\) and \(\angle E\)).
- HL (Hypotenuse - Leg): For HL, we need to know about the hypotenuse and a leg of right - angled triangles. We are not given any information about the hypotenuse of these right - angled triangles (\(AC\) and \(DF\)).
- SAS (Side - Angle - Side): For SAS, we need two sides and the included angle. We are only given one side (\(BC = EF\)) and two angles (\(\angle A=\angle D\) and \(\angle B=\angle E\)).
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C. AAS