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Question
triangle pqr has vertices p(-2, 6), q(-8, 4), and r(1, -2). it is translated according to the rule (x, y) → (x - 2, y - 16). what is the y - value of p? \bigcirc -18 \bigcirc -16 \bigcirc -12 \bigcirc -10
Step1: Identify P's y-coordinate
Original P: $(-2, 6)$, so $y=6$.
Step2: Apply translation rule to y
Rule: $y \to y - 16$. Calculate: $6 - 16 = -10$.
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