Question

1. triangle por with vertices p(-13, -3), q(-7, 3), and r(-6, -2): 90° clockwise rotation about point r

6.
p(_,_)
q(_,_)
r(_,_)

Explanation:

Step1: Translate points

Subtract the coordinates of point \(R(-6,-2)\) from points \(P(-13,-3)\) and \(Q(-7,3)\)
For \(P\): \((-13 - (-6),-3-(-2))=(-7,-1)\)
For \(Q\): \((-7 - (-6),3-(-2))=(-1,5)\)

Step2: Apply \(90^{\circ}\) clockwise rotation formula

The formula for \(90^{\circ}\) clockwise rotation of a point \((x,y)\) is \((y,-x)\)
For translated \(P(-7,-1)\): \((-1,7)\)
For translated \(Q(-1,5)\): \((5,1)\)

Step3: Translate back

Add the coordinates of point \(R(-6,-2)\) to the rotated points
For \(P'\): \((-1+(-6),7+(-2))=(-7,5)\)
For \(Q'\): \((5+(-6),1+(-2))=(-1,-1)\)
Since rotation about \(R\), \(R'\) has the same coordinates as \(R\), so \(R'(-6,-2)\)

Answer:

\(P'(-7,5)\), \(Q'(-1,-1)\), \(R'(-6,-2)\)