Question

triangle jkl is similar to triangle mno. find the measure of side no. round your answer to the nearest tenth if necessary. figures are not drawn to scale.

Explanation:

Step1: Set up the proportion

Since \(\triangle JKL\sim\triangle MNO\), the ratios of corresponding sides are equal. Let \(NO = x\). The proportion is \(\frac{NO}{KL}=\frac{OM}{JL}\). Substituting the known values: \(\frac{x}{31}=\frac{5}{17}\).

Step2: Solve for \(x\)

Cross - multiply: \(17x=31\times5\). Then \(17x = 155\). Divide both sides by \(17\): \(x=\frac{155}{17}\approx9.1\).

Answer:

\(9.1\)