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Question
triangle def is congruent to △ghj by the sss theorem. which rigid transformation is required to map △def onto △ghj? dilation reflection rotation translation
Step1: Recall rigid transformation properties
Rigid transformations (reflection, rotation, translation) preserve shape and size. Dilation is not a rigid transformation as it changes size. Since \(\triangle DEF\cong\triangle GHJ\) (same - size), dilation is out.
Step2: Analyze orientation
Translation moves a figure without rotation or reflection. If we look at the orientation of the triangles: \(\triangle DEF\) and \(\triangle GHJ\) have the same - side markings (congruent sides), but the order of vertices (if we consider the base) is such that a reflection (a flip over a line) is not needed. A rotation (turning around a point) is also not the case.
Step3: Check translation
Translation slides a figure. We can think of moving \(\triangle DEF\) (without rotating or reflecting) to map it onto \(\triangle GHJ\) since the side - length relationships (from SSS) and the general shape (congruent) can be achieved by just shifting the position of \(\triangle DEF\) in the plane.
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