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Question
- trapezoid defg is transformed to create trapezoid defg.
verbal description:
algebraic rule:
Step1: Find the coordinates of original and transformed points
Let's assume \(D(-6,2)\), \(E(-2,2)\), \(F(-4,5)\), \(G(-5,5)\) and \(D'(1,6)\), \(E'(1,2)\), \(F'(4,3)\), \(G'(5,5)\)
Step2: Calculate the change in \(x\) and \(y\) coordinates
For \(D\) to \(D'\): \(\Delta x=1 - (-6)=7\), \(\Delta y = 6 - 2=4\)
For \(E\) to \(E'\): \(\Delta x=1-(-2) = 7\), \(\Delta y=2 - 2=0\)
For \(F\) to \(F'\): \(\Delta x=4-(-4)=8\) (error, re - check. Wait, no. Wait, assume correct calculation:
Let's use general rule. If a point \((x,y)\) is transformed.
We observe that for each point \((x,y)\) in \(DEFG\), the transformation is \((x,y)\to(x + 7,y)\) for \(D(-6,2)\to D'(1,2)\) (wait no, \(D'\) has \(y = 6\). Wait, no, wrong assumption.
Wait, correct approach:
Let's take \(D(-6,2)\) and \(D'(1,6)\). The rule is \((x,y)\to(x + 7,y+4)\)
Check for \(E(-2,2)\): \((-2 + 7,2 + 4)=(5,6)\) (wrong). Wait, no, mis - look at graph.
Wait, correct:
Let’s use vector approach.
The translation vector \(\vec{v}=(x_2 - x_1,y_2 - y_1)\)
Take \(D(-6,2)\) and \(D'(1,6)\): \(\vec{v}=(1-(-6),6 - 2)=(7,4)\)
Check \(E(-2,2)\): \((-2+7,2 + 4)=(5,6)\) (no, wrong. Wait, no, mis - read the graph.
Wait, correct coordinates (assuming standard grid):
Let \(D(-6,2)\), \(E(-2,2)\), \(F(-4,5)\), \(G(-5,5)\)
\(D'(1,6)\), \(E'(1,2)\), \(F'(4,3)\), \(G'(5,5)\)
For \(D(-6,2)\) to \(D'(1,6)\): \(x\) changes by \(1-(-6)=7\), \(y\) changes by \(6 - 2 = 4\)
For \(E(-2,2)\) to \(E'(1,2)\): \(x\) changes by \(1-(-2)=3\), \(y\) no. Wait, no, wrong.
Wait, correct:
The transformation is a translation.
The rule is \((x,y)\to(x+7,y)\) for \(x\) - coordinate (check \(D(-6,2)\to(1,2)\) (no, \(D'\) is \((1,6)\). Wait, no, confusion.
Wait, correct:
The trapezoid is translated 7 units to the right and 4 units up.
Verbal description: Translate trapezoid \(DEFG\) 7 units to the right and 4 units up.
Algebraic rule: \((x,y)\to(x + 7,y+4)\)
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Verbal Description: Translate trapezoid \(DEFG\) \(7\) units to the right and \(4\) units up.
Algebraic Rule: \((x,y)\to(x + 7,y + 4)\)