Question

translate quadrilateral adcb 5 units to the left and 2 units down. what are the coordinates of new quadrilateral a dc b? (1 point) a(-1,0), d(-1,5), c(4,2), b(2,-1) a(9,-4), d(9,1), c(13,-2), b(12,-5) a(-1,-4), d(-1,1), c(4,-2), b(2,-5) a(0,0), d(0,5), c(13,2), b(12,-1)

Explanation:

Step1: Find coordinates of A and B

From the graph, \( A(4, -2) \), \( B(7, -3) \) (assuming D and C are \( D(4, 3) \), \( C(9, 0) \) by observing the quadrilateral's shape).

Step2: Apply translation (left 5, down 2)

For a point \((x, y)\), translation left 5: \( x' = x - 5 \), down 2: \( y' = y - 2 \).

• For \( A(4, -2) \): \( A' = (4 - 5, -2 - 2) = (-1, -4) \)
• For \( D(4, 3) \): \( D' = (4 - 5, 3 - 2) = (-1, 1) \)
• For \( C(9, 0) \): \( C' = (9 - 5, 0 - 2) = (4, -2) \)
• For \( B(7, -3) \): \( B' = (7 - 5, -3 - 2) = (2, -5) \)

Answer:

\( A'(-1, -4), D'(-1, 1), C'(4, -2), B'(2, -5) \) (corresponding to the third option: \( A'(-1, -4), D'(-1, 1), C'(4, -2), B'(2, -5) \))