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training field is formed by joining a rectangle and two semicircles, as…

Question

training field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 91 m long and 63 m wide. what is ngth of a training track running around the field? (use the value 3.14 for π, and do not round your answer. be sure to include the correc

Explanation:

Step1: Find the circumference of the circle (two semicircles)

The diameter of the semicircles is 63 m, so the radius \( r=\frac{63}{2} \) m. The circumference of a full circle is \( C = \pi d \) (where \( d \) is the diameter). So the length of the two semicircles (which make a full circle) is \( C=\pi\times63 \). Using \( \pi = 3.14 \), we get \( 3.14\times63 = 197.82 \) m.

Step2: Find the length of the two straight sides (from the rectangle)

The rectangle has a length of 91 m, and there are two such sides. So their total length is \( 2\times91=182 \) m.

Step3: Find the total length of the track

Add the length of the circular part and the length of the two straight sides. So total length \( = 197.82+182 = 379.82 \) m.

Answer:

379.82 m