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a training field is formed by joining a rectangle and two semicircles, …

Question

a training field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 82 m long and 50 m wide. what is the length of a training track running around the field? (use the value 3.14 for π, and do not round your answer. be sure to include the correct unit in your answer.)

Explanation:

Step1: Calculate the circumference of the two semicircles (which is equivalent to the circumference of one full circle)

The formula for the circumference of a circle is \(C = \pi d\). Given \(d = 50\) m and \(\pi=3.14\), we have \(C = 3.14\times50\).

Step2: Calculate the length of the two straight - line parts of the track

The length of each straight - line part is \(82\) m, and there are two such parts. So the total length of the straight - line parts is \(2\times82\).

Step3: Calculate the total length of the track

The total length \(L\) of the track is the sum of the circumference of the circle and the lengths of the two straight - line parts. So \(L=3.14\times50 + 2\times82\).

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Answer:

\(321\) m