Question

1. a train travels 65 miles per hour for 3 hours. complete the table.

time (hours)	distance (miles)	miles per hour
	195

Explanation:

Step1: Recall the formula for distance

The formula for distance is \( \text{distance} = \text{speed} \times \text{time} \), where speed is in miles per hour and time is in hours. The speed here is 65 miles per hour.

Step2: Fill in the second row (time = 2 hours)

For time = 2 hours, calculate distance: \( \text{distance} = 65 \times 2 = 130 \) miles. The speed remains 65 miles per hour.

Step3: Fill in the third row (time = 3 hours)

For time = 3 hours, calculate distance: \( \text{distance} = 65 \times 3 = 195 \) miles (which matches the given distance in the last row). Wait, actually, the last row has distance 195, so time for that row is \( \text{time} = \frac{\text{distance}}{\text{speed}} = \frac{195}{65} = 3 \) hours. Let's correct the rows:

• Second row: time = 2, distance = 65×2 = 130, speed = 65.
• Third row: time = 3, distance = 65×3 = 195, speed = 65. Wait, the table has four rows? Wait the first row is time=1, distance=65, speed=65. Then the next rows:

Row 2: time = 2, distance = 65×2 = 130, speed = 65.

Row 3: time = 3, distance = 65×3 = 195, speed = 65. But the last row has distance=195, so time=3, speed=65. Wait maybe the table has three rows after the first? Wait the original table:

First row: time=1, distance=65, speed=65.

Second row: time=2, distance=130, speed=65.

Third row: time=3, distance=195, speed=65. Wait the last row (fourth row) has distance=195, so time=3, speed=65. Wait maybe the table is:

time (hours)	distance (miles)	miles per hour
2	130	65
3	195	65

Wait the problem says "for 3 hours", so we need to fill the table for time 1, 2, 3 hours (and the last row has distance 195, which is time 3). Let's structure the table:

• Row 2 (time=2): distance = 65×2 = 130, speed=65.
• Row 3 (time=3): distance = 65×3 = 195, speed=65.
• The last row (with distance=195) has time=3, speed=65.

So filling the table:

time (hours)	distance (miles)	miles per hour
2	130	65
3	195	65

Wait the original table has a row with distance=195, so that's time=3. So the second row (time=2) has distance=130, speed=65. The third row (time=3) has distance=195, speed=65. The last row (the one with distance=195) is time=3, speed=65.

Answer:

The completed table is:

time (hours)	distance (miles)	miles per hour
2	130	65
3	195	65

(If the table has four rows, maybe a typo, but based on the problem, the train travels for 3 hours, so time 1,2,3 with distances 65,130,195 and speed 65 throughout.)