Question

1. if tims fishing pole has a weight capacity of 3,250 grams, will he be able to catch a fish that weighs $6\frac{1}{2}$ pounds? keep in mind that 1 pound is approximately 453.6 grams.

tims fishing pole is strong enough to catch a $6\frac{1}{2}$ -pound fish.
tim will not be able to use his fishing pole because the fishing line he is using will break.
no, because tims fishing pole is too short.
no, his poles weight limit will not support a $6\frac{1}{2}$ -pound fish.

Explanation:

Step1: Convert pounds to grams

First, we need to convert the weight of the fish from pounds to grams. The fish weighs \( 6\frac{1}{2} \) pounds, which is \( 6.5 \) pounds. We know that 1 pound is approximately 453.6 grams. So we multiply the weight in pounds by the conversion factor: \( 6.5\times453.6 \)

Step2: Calculate the weight in grams

\( 6.5\times453.6 = 2948.4 \) grams. Now we compare this weight with the weight capacity of the fishing pole, which is 3250 grams. Since \( 2948.4 < 3250 \), the fishing pole can support the fish.

Answer:

Tim's fishing pole is strong enough to catch a \( 6\frac{1}{2} \)-pound fish.