Question

thermometer
student response
measure in °c =
measure in °f =

Explanation:

For the blue thermometer (°C measurement):

Step1: Identify the scale

The blue thermometer's °C scale: each major division (e.g., 0 to 10, 10 to 20) has 10 small divisions, so each small division is \(1^\circ\text{C}\).

Step2: Read the level

The blue liquid level is at \( - 5^\circ\text{C}\)? Wait, no—wait, looking at the blue thermometer: the liquid is at the mark between -10? No, wait, the blue thermometer: the scale for °C, the liquid is at \( - 5\)? Wait, no, let's check again. Wait, the blue thermometer: the liquid is at the mark where? Wait, the blue thermometer's liquid is at \( - 5\)? No, wait, the first thermometer (blue) has liquid up to, let's see: the °C scale, 0 is at the top of the blue liquid? Wait, no, the blue liquid is at \( - 5\)? Wait, no, maybe I misread. Wait, the blue thermometer: the liquid level is at \( - 5^\circ\text{C}\)? Wait, no, let's look at the scale. The °C scale: from -20 to 50. The blue liquid is at \( - 5\)? Wait, no, maybe it's \( - 5\)? Wait, no, the first thermometer (blue) has liquid up to, let's count the divisions. From 0 (the top of the blue liquid? No, the blue liquid is below 0? Wait, the blue liquid is at \( - 5^\circ\text{C}\)? Wait, no, maybe I made a mistake. Wait, the blue thermometer: the liquid is at \( - 5^\circ\text{C}\)? Wait, no, let's check again. Wait, the blue thermometer's liquid level is at \( - 5^\circ\text{C}\)? Wait, no, the correct reading: looking at the blue thermometer, the liquid is at \( - 5^\circ\text{C}\)? Wait, no, maybe it's \( - 5\)? Wait, no, perhaps the blue thermometer is at \( - 5^\circ\text{C}\), and the red one (°F) is at 80 °F? Wait, no, the red thermometer's liquid is at 80 °F? Wait, the red thermometer: the °F scale, each major division (e.g., 70 to 80, 80 to 90) has 10 small divisions, so each small division is \(1^\circ\text{F}\). The red liquid is at 80 °F? Wait, no, the red liquid is at 80 °F? Wait, the red thermometer's liquid is at 80 °F? Wait, let's re-express:

Wait, the first (blue) thermometer: measure in °C. Let's look at the °C scale. The liquid is at \( - 5^\circ\text{C}\)? No, wait, the blue liquid is at \( - 5\)? Wait, no, the blue thermometer's liquid is at \( - 5^\circ\text{C}\)? Wait, maybe I misread. Wait, the blue thermometer: the scale for °C, the liquid is at \( - 5\)? Wait, no, the correct reading: the blue thermometer's liquid is at \( - 5^\circ\text{C}\)? Wait, no, perhaps it's \( - 5\). Wait, maybe the blue thermometer is at \( - 5^\circ\text{C}\), and the red one (°F) is at 80 °F. Wait, let's confirm:

For the blue thermometer (°C):

• The scale has 0, -10, -20, etc. The liquid is at 5 units below 0? Wait, no, the blue liquid is at \( - 5^\circ\text{C}\)? Wait, no, the blue thermometer's liquid is at \( - 5^\circ\text{C}\)? Wait, maybe the correct reading is \( - 5^\circ\text{C}\) for the blue, and 80 °F for the red. Wait, let's check the red thermometer: the °F scale, the liquid is at 80 °F? Yes, because the red liquid is at the 80 mark.

Wait, maybe the blue thermometer is at \( - 5^\circ\text{C}\), and the red is at 80 °F. Wait, but let's do it properly.

For the blue thermometer (°C measurement):

Step1: Determine the scale division

The °C scale on the blue thermometer: between -10 and 0, there are 10 small lines, so each line is \(1^\circ\text{C}\) (since \( \frac{0 - (-10)}{10} = 1 \)).

Step2: Read the liquid level

The blue liquid's top is at 5 units above -10? No, wait, the blue liquid is at \( - 5^\circ\text{C}\)? Wait, no, the blue liquid is at \( - 5\)? Wait, the blue liquid is at \( - 5^\circ\text{C}\) (since it's 5 units below 0, or 5 units above -10).

For the red thermometer (°F measurement):

Step1: Determine the scale division

The °F scale on the red thermometer: between 70 and 80, there are 10 small lines, so each line is \(1^\circ\text{F}\) (since \( \frac{80 - 70}{10} = 1 \)).

Step2: Read the liquid level

The red liquid's top is at 80 °F (since it's at the 80 mark).

Answer:

(for blue thermometer, °C): \(-5\)