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Question
there is a right triangle with one leg labeled 8 mi, the hypotenuse labeled 16 mi, and the other leg labeled x. the options are: a) $8\sqrt{3}$ miles, b) $16\sqrt{2}$ miles, c) $8\sqrt{2}$ miles, d) $16\sqrt{3}$ miles.
Step1: Apply Pythagorean theorem
$x^2 + 8^2 = 16^2$
Step2: Calculate squares
$x^2 + 64 = 256$
Step3: Solve for $x^2$
$x^2 = 256 - 64 = 192$
Step4: Find square root of $x^2$
$x = \sqrt{192} = 8\sqrt{3}$
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A. $8\sqrt{3}$ miles